Question #251901

The line through the point (1,0,6) and perpendicular to the plane x+3y+z=5x+3y+z=5 has vector equation r=(u,v,w)=(a,b,c)+t(d,e,f)\mathbf{r}=( u,v,w )=( a,b,c )+ t (d,e,f ) where t is a parameter.


Making use of the parameter t, find the values of: u; v and w



1
Expert's answer
2021-10-18T06:34:00-0400
r=(1,0,6)+t(1,3,1)=(u,v,w)r=(1,0,6)+t(1,3,1)=(u,v,w)

u=1+t,v=3t,w=6+tu=1+t, v=3t, w=6+t


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