Suppose u; v € V and ||u|| = ||v|| = 1 with < u; v > = 1: Prove that u = v
<u,v>=||u||⋅\cdot⋅ ||v||cosθ\thetaθ
1=1⋅\cdot⋅1cosθ\thetaθ
cosθ=1\theta=1θ=1
θ=0°\theta=0\degreeθ=0°
So, the magnitudes of the vectors are equal, and the angle between them is 0°\degree°. That is the vectors are equal.
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