first of all, we need to transform the equation to the canonical form
a2(xβx0β)2ββb2(yβy0β)2β=1β , x0β and y0β are coordinates of the center,
3x2+6xβ2y2β8y=6
(3x2+6x+3)β(2y2+8y+8)=1
31β(x+1)2ββ21β(y+2)2β=1
O (-1,-2) is the center
a=31βββ0.6
b=21βββ0.7
what is a and b:
(instead of the origin, there can be any point that is the center of the hyperbola)
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hi, it would really make my day if someone was able to answer my question ASAP. Thanks