Draw the ellipse with the equation: 2𝑥 2 + 𝑦 2 + 4𝑥 − 9𝑦 = 7
first of all, we need to transform the equation to the canonical form
(x−x0)2a2+(y−y0)2b2=1\boxed{\frac {(x-x_0)^2} {a^2} + \frac{(y-y_0)^2} {b^2} = 1}a2(x−x0)2+b2(y−y0)2=1 - x0x_0x0 and y0y_0y0 - center coordinates
2x2+4x+y2−9y=72x^2 + 4x + y^2-9y=72x2+4x+y2−9y=7
(2x2+4x+2)+(y2−9y+20.25)=29.25(2x^2 +4x +2) +(y^2 -9y+20.25) = 29.25(2x2+4x+2)+(y2−9y+20.25)=29.25
2(x+1)2+(y−4.5)2=29.252(x+1)^2+(y-4.5)^2 = 29.252(x+1)2+(y−4.5)2=29.25
(x+1)214.625+(y−4.5)229.25=1\dfrac{(x+1)^2}{14.625} + \dfrac{(y - 4.5)^2}{29.25} = 114.625(x+1)2+29.25(y−4.5)2=1
O(-1; 4.5) - center
a=14.625≈3.8a = \sqrt{14.625} \thickapprox 3.8a=14.625≈3.8 - minor semiaxis
b=29.25≈5.4b = \sqrt{29.25} \thickapprox 5.4b=29.25≈5.4 - major semiaxes
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It would really make my day if someone answered this question right away. Thanks