State whether the following statements are true or false. Justify your answer with a brief explanation or with a counter-example.
(a) The curve x4 + y4 = 4a2xy is symmetric with respect to the origin.
(b) The direction cosines of the line x = — y, z=0 are 1/√2, -1/√2,0
(c) The section of 2x² + y²= 2 (1 — z²) by the plane x + 2 = 0 is a hyperbola.-
(d) The xy-plane intersects the sphere
x²+ y² + z² + 2x + 2y — z = 2 in a great circle.
(e) If the projection of a line segment AB on another line is the line segment CD, then
IABI = ICDI•
a) true
b) true
Since the vector "v=(1,-1,0)" is parallel to the line "x=-y, z=0" and "|v|=\\sqrt{2}" , we conclude that "cos \\alpha=1\/\\sqrt{2}, cos\\beta=-1\/\\sqrt{2}, cos=0\/\\sqrt{2}=0"
c) false
The general equation of a hyperbola is
"\\frac{x^2}{a^2}-\\frac{y^2}{b^2}=1"
Let us find the section of "2x^ \n2\n +y^ \n2\n =2(1\u2212z^ \n2\n )" by the plane "x+2=0"
"2(\u22122)^ \n2\n +y^ \n2\n =2(1\u2212z^ \n2\n )"
"8+y^ \n2\n =2\u22122z^\n2"
"y^ \n2\n +2z^ \n2\n =\u22126"
Since the eqution has no real solution, the plane "x+2=0" does not intersect
"2x^ \n2\n +y^ \n2\n =2(1\u2212z^ \n2\n )". The equation "y^ \n2\n +2z^ \n2\n =\u22126" is not a hyperbola equation.
d) false
The xy-plane intersects the sphere "x^ \n2\n +y^ \n2\n +z^ \n2\n +2x+2y\u2212z=2" in a great circle if and only if the center of this sphere belong to "xy"-plane. Let us rewrite the equation of the sphere in the the following form: "(x+1)^ \n2\n +(y+1)^ \n2\n +(z\u22121\/2\n\u200b\t\n )^ \n2\n =2+1+1+1\/4 =17\/4" . It follows that "M(\u22121,\u22121, \n1\/2\n\u200b\t\n )" is the center of the sphere. Taking into account that the third coordinate of "M" is not equal to 0, we conclude that the center of the sphere does not belong to the "xy"-plane, and therefore, the sphere "x^2 \n\n +y^ \n2\n +z^ \n2\n +2x+2y\u2212z=2" does not intersect the "xy" -plane in a great circle.
e) false
Let consider any line segment "AB" with "\u2223AB\u2223=2". The projection of a line segment "AB" on another line is the line segment "CD" formed by the projections of the end points of the line segment "AB" on this line. If we choose such a line "l" that the segment "AB" is perpendicular to "l", then the points A and B projects on the same point "C=D" of the line "l", and therefore, "|CD|=0".
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