We have semielliptical ceiling, so we have to consider it as a half of ellipse.
General form of ellipse is; (x-h)2/a2+(y-h)2/b2=1;
a is the length of a major radius;
b is the the length of minor radius;
in our case the length of the room is 2a and equals to 34 m, a=17;
the height of the room is taken as b and it equals to 8 m;
h and k are equal to 0,
So our ellipse is x2/289+y2/64=1;
Now we need to find the distance between the center and the foci, c;
c2=a2-b2 , c2= 289-64, c=15;
Answer is 15 m;
People should stand 15 m away from the center.
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