Question #145223
Identify the type of the conic 4(x-2y+1)^2 +9(2x+y+2)^2 = 25
1
Expert's answer
2020-11-24T15:26:34-0500

Given 4(x2y+1)2+9(2x+y+2)24(x-2y+1)^2 + 9(2x+y+2)^2 =25= 25

Divide through by 25, this gives us

(x2y+1)2254+(2x+y+2)2259\frac{(x-2y+1)^2}{\frac{25}{4}} + \frac{(2x+y+2)^2}{\frac{25}{9}}

=(x(2y1))2(52)2+((y(2x2))2(53)2=1=\frac{(x-(2y-1))^2}{(\frac{5}{2})^2} + \frac{((y-(-2x-2))^2}{(\frac{5}{3})^2}=1

which satisfies the equation of ellipse

(x1)2a2+(y1)2b2=1\frac{(x1)^2}{a^2} + \frac{(y1)^2}{b^2}=1 ,

where x1,y1x1, y1 are new variables.

Therefore the conic is an ellipse.



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