Given 4(x−2y+1)2+9(2x+y+2)2 =25
Divide through by 25, this gives us
425(x−2y+1)2+925(2x+y+2)2
=(25)2(x−(2y−1))2+(35)2((y−(−2x−2))2=1
which satisfies the equation of ellipse
a2(x1)2+b2(y1)2=1 ,
where x1,y1 are new variables.
Therefore the conic is an ellipse.
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