The equation of the circle of radius R with center at (a,b) is (x−a)2+(y−b)2=R2. In our case, (x−2)2+(y−5)2=R2. Since the circle passing through (−5,5), we have (−5−2)2+(5−5)2=R2, and consequently R=7. On the other hand, since the circle passing through (−1,1), we have (−1−2)2+(1−5)2=R2, and therefore R=5. This contradiction shows that such a circle does not exist.
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