Solution
Given vectors are
a=(2i+3j)
b=(4i-2j)
c=(1i+4j)
Now volume of shape is given by
"V=a.(b\u00d7c)" ................ eq. 1
Now
Cross product of vector b and c
(b×c)=18 k
And
a.(b×c)=(2i+3j). (18k) =0
Now putting these value in equation 1
Volume of given shape
V=0
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