3x2+3y2+6x−9y=2,3x2+3y2+6x−9y−2=0,x2+y2+2x−3y−2/3=03x ^2 + 3y ^2 + 6x − 9y = 2,\\3x ^2 + 3y^ 2 + 6x − 9y - 2=0,\\ x ^2 + y^ 2 + 2x − 3y - 2/3=03x2+3y2+6x−9y=2,3x2+3y2+6x−9y−2=0,x2+y2+2x−3y−2/3=0
From here we can see that the center is (−1,3/2)(-1,3/2)(−1,3/2) and radius is 12+1.52+2/3=1.97\sqrt{1^2+1.5^2+2/3}=1.9712+1.52+2/3=1.97
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