Question #123712
If the tangents at two points of a parabola are at right angles, then show that they intersect at a point on the directrix.
1
Expert's answer
2020-06-24T18:09:20-0400

We remind that the parabola is the locus of points that are equidistant from both focus and the directrix . We assume that the focus has coordinates (x0,y0)(x_0,y_0) and y=y1y=y_1 is an equation of directrix. The following equality has to be satisfied:

yy1=(xx0)2+(yy0)2|y-y_1|=\sqrt{(x-x_0)^2+(y-y_0)^2}

From the latter, by direct calculations, we get:

(yy1)2=(xx0)2+(yy0)2y=(xx0)22(y0y1)(y-y_1)^2=(x-x_0)^2+(y-y_0)^2\,\,\,\Longrightarrow\,\,\,\,y=\frac{(x-x_0)^2}{2(y_0-y_1)} .

We remind that the equation of the tangent line to the curve y=f(x)y=f(x) (see e.g., https://en.wikipedia.org/wiki/Tangent) at point x~\tilde{x} has the form:

y=f(x~)+f(x~)(xx~)y=f(\tilde{x})+f'(\tilde{x})(x-\tilde{x})

From this we receive that equation of the tangent line to parabola has the form:

y=(x~x0)22(y0y1)+x~y0y1(xx~)y=\frac{(\tilde{x}-x_0)^2}{2(y_0-y_1)}+\frac{\tilde{x}}{y_0-y_1}(x-\tilde{x})

Suppose that we have two tangent lines at points x~1\tilde{x}_1 and x~2\tilde{x}_2. The tangent of the angle between those two lines is (see https://en.wikipedia.org/wiki/List_of_trigonometric_identities):

tanα=x~1x~2y0y11+x~2y0y1x~1y0y1=x~1x~2y0y1+x~2x~1tan\,\alpha=\frac{\frac{\tilde{x}_1-\tilde{x}_2}{y_0-y_1}}{1+\frac{\tilde{x}_2}{y_0-y_1}\cdot\frac{\tilde{x}_1}{y_0-y_1}}=\frac{\tilde{x}_1-\tilde{x}_2}{y_0-y_1+{\tilde{x}_2}\tilde{x}_1}

The tangent tends to infinity for the angles close to 900

This means, that y0y1+x~2x~1=0y_0-y_1+{\tilde{x}_2}\tilde{x}_1=0. From the latter we found that x~2=y1y0x~1\tilde{x}_2=\frac{y_1-y_0}{\tilde{x}_1}. In order to find the point, where two lines intersect, we have the equality:

(x~1x0)22(y0y1)+x~1y0y1(xx~1)=(x~2x0)22(y0y1)+x~2y0y1(xx~2)\frac{(\tilde{x}_1-x_0)^2}{2(y_0-y_1)}+\frac{\tilde{x}_1}{y_0-y_1}(x-\tilde{x}_1)=\frac{(\tilde{x}_2-x_0)^2}{2(y_0-y_1)}+\frac{\tilde{x}_2}{y_0-y_1}(x-\tilde{x}_2)

After simplifications we receive:

x=x0+x~1+x~22x=x_0+\frac{\tilde{x}_1+\tilde{x}_2}{2}

We substitute the latter in equation for the tangent line and receive the y-coordinate of the point, where tangent lines intersect. We point out, that in general it is not equal to y1y_1



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