we know that if
r→=xi^+yj^+zk^\overrightarrow{r}= x\hat{i}+y\hat{j}+z\hat{k}r=xi^+yj^+zk^ then magnitude of r→\overrightarrow{r}r is given by
here r→=−i^+2j^+2k^\overrightarrow{r} = -\hat{i} + 2\hat{j} + 2\hat{k}r=−i^+2j^+2k^
∴∣r→∣=(−1)2+22+22\therefore |\overrightarrow{r}|=\sqrt{(-1)^2+2^2+2^2}∴∣r∣=(−1)2+22+22
or,∣r→∣=1+4+4or,|\overrightarrow{r}| = \sqrt{1+4+4}or,∣r∣=1+4+4
or,∣r→∣=9or,|\overrightarrow{r}|=\sqrt{9}or,∣r∣=9
or,∣r→∣=3.or,|\overrightarrow{r}|=3.or,∣r∣=3.
Answer: magnitude of r→ is 3.\overrightarrow{r} \,\text{is}\,3.ris3.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments