Question #122094
Given r= -i+2j+2k, find the magnitude of r
1
Expert's answer
2020-06-15T15:53:16-0400

we know that if

r=xi^+yj^+zk^\overrightarrow{r}= x\hat{i}+y\hat{j}+z\hat{k} then magnitude of r\overrightarrow{r} is given by


r=x2+y2+z2|\overrightarrow{r}|=\sqrt{x^2+y^2+z^2}

here r=i^+2j^+2k^\overrightarrow{r} = -\hat{i} + 2\hat{j} + 2\hat{k}


r=(1)2+22+22\therefore |\overrightarrow{r}|=\sqrt{(-1)^2+2^2+2^2}

or,r=1+4+4or,|\overrightarrow{r}| = \sqrt{1+4+4}

or,r=9or,|\overrightarrow{r}|=\sqrt{9}

or,r=3.or,|\overrightarrow{r}|=3.


Answer: magnitude of ris3.\overrightarrow{r} \,\text{is}\,3.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS