Question #110744
If \\(a=3i-2j+k\\), \\(b=2i-4j-3k\\) and \\(c=-i+2j+2k\\), find the magnitude of \\(a+b+c\\)
1
Expert's answer
2020-04-20T17:27:45-0400

Analytic Geometry

We need to find the magnitude of the sum of given vectors.

Solution:


The given vectors are,

a=3i2j+kb=2i4j3kc=i+2j+2k\vec a = 3i-2j+k\\ \vec b = 2i-4j-3k\\ \vec c =-i+2j+2k

Sum of the vectors =a+b+c= \vec a + \vec b + \vec c

=3i2j+k+2i4j3k+i+2j+2k= 3i-2j+k + 2i-4j-3k + -i+2j+2k

=4i4j= 4i - 4 j

Magnitude of the given vectors

=a+b+c=42+(4)2=(16+16)=32= |\vec a + \vec b + \vec c| = \sqrt {4^2 + (-4)^2} = \sqrt {(16 +16)} = \sqrt {32}


=42= 4 \sqrt 2

Magnitude of the given vectors =424 \sqrt 2


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS