Let the line be y=3x+4
Let's find two unit vectors that are parallel to that line.
The slope the given line is 3.
Suppose that, this line makes an angle of "\\theta" with the +ve direction of the X−Axis.
Then, the unit vector "\\overline{u}=(\\cos\\theta,\\sin\\theta)" is parallel to the line.
By the definition of slope, we have
"\\tan\\theta=3"
therefore
"\\sec^2\\theta=1+\\tan^2\\theta=10"
"cos\\theta=\\frac{1}{\\sec\\theta}=\\pm\\frac{1}{\\sqrt{10}}"
"\\sin\\theta=\\sqrt{1-cos^2\\theta}=\\sqrt{1-\\frac{1}{10}}=\\pm\\frac{3}{\\sqrt{10}}"
Hence "\\overline{u}(\\frac{1}{\\sqrt{10}},\\frac{3}{\\sqrt{10}})" and "\\overline{v}(-\\frac{1}{\\sqrt{10}},-\\frac{3}{\\sqrt{10}})" are two vectors, parallel to the line y=3x+4
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