It follows that John can do "\\frac{1}2" part of the job per one day, Peter can do "\\frac{1}3" part of the job per one day, and Danny can do "\\frac{1}6" part of the job per one day. Taking into accounrt that "\\frac{1}{2}+\\frac{1}3+\\frac{1}6=\\frac{3+2+1}{6}=\\frac{6}{6}=1,"
we conclude that it will take one day all of them together to finish the job.
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