Find the two consecutive integers that have a sum of 39.
Let the two consecutive integers be n and (n+1)
n+(n+1)=39n+(n+1)=39n+(n+1)=39
2n=382n=382n=38
n=19n=19n=19
n+1=19+1=20n+1=19+1=20n+1=19+1=20
So the two integers are 19 and 20
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