Answer to Question #237446 in Algebra for Mr. Lee

Question

Four years ago, the sum of the ages of Bill and Jane was 45.

Six year from now, twice jane’s age will be 28 more than

Bill’s age then. How old is jane now?

Answer 1

Four years ago ;

Bill (x) =$x-4$

Jane (Y) =$y-4$

Sum of their ages =x+y-8=45 (x+y=53).........(i)

Six years from now ;

$2y-x=28$...........(ii)

Combining equation (i) and (ii) by substitution ;

$x+y=53$

$2y-x=28$

$2y-53+y=28$

3y=81

y=27

Thus x=26 and y=27

Jane's age now is 27yrs