Question #208426

. Find the term independent of x in the expansion of (x^ 3+2/x)^ 20


Expert's answer

By the Binomial Theorem


(a+b)n=(n0)anb0+(n1)an−1b1+(n2)an−2b2(a+b)^n=\dbinom{n}{0}a^nb^0+\dbinom{n}{1}a^{n-1}b^{1}+\dbinom{n}{2}a^{n-2}b^{2}

+...+(nn−1)a1bn−1+(nn)a0bn+...+\dbinom{n}{n-1}a^{1}b^{n-1}+\dbinom{n}{n}a^{0}b^{n}

We have a=x3,b=2x=2x−1,n=20.a=x^3, b=\dfrac{2}{x}=2x^{-1}, n=20.

If the term is independent of x,x, then


(x3)20−k(x−1)k=x0,(x^3)^{20-k}(x^{-1})^k=x^{0},

60−3k−k=060-3k-k=0

k=15k=15

(2015)(x3)20−15(2x)15=15504(32768)\dbinom{20}{15}(x^3)^{20-15}\bigg(\dfrac{2}{x}\bigg)^{15}=15504(32768)

=508035072=508035072



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