Answer to Question #208310 in Algebra for Zibu

Question

1.) Increase 9900 in the ratio 9:4

2.) A certain amount of money is divided among A,B and C on the ratio 10:4:3. If B and C together receive $665, what amount is divided among the three

3.) At the market you pay $45,50 for half a kilogram of fish.What would you pay for 2,25kg?

Answer 1

1)

$$9900\cdot(\dfrac{9}{4})=\dfrac{9900\cdot9}{4}=\dfrac{89100}{4}=22275$$

2)

Let $x=$ the amount of money in 1 part. Then A receives $10x$ dollars, B receives $4x$ dollars, and C receives $3x$ dollars.

Given B and C together receive $665

$$4x+3x=665$$

$$7x=665$$

$$x=95$$

Then the total amount is

$$(10+4+3)(95)=1615$$

1615 dollars are divided among A,B and C.

3)

$$\begin{matrix} 0.5\ kg & & \$45.50 \\ 2.25\ kg & & \$x \end{matrix}$$

$$x=\dfrac{2.25(45.50)}{0.5}$$

$$x=\$204.75$$

We would pat $204.75 for 2.25 kg of fish.