Prove that any even power of a Nonzero integer is positive. That is, if X does not equal to zero in integers, then X2n is positive for every positive integer n.
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Expert's answer
2021-05-14T11:07:06-0400
x=0,x2>0 because
ifx>0,x2=x∗x>0,ifx<0,x2=x∗x=(−x)∗(−x)>0
x2n=(x2)n>0
since raising a positive number to a power keeps it positive
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