z2 -4z+29=0
By the quadratic formula;
"z=\\frac{-b\\pm \\sqrt{b^2-4ac}}{2a}"
where;
a=1
b=4
c=29
"z=\\frac{-(-4)\\pm\\sqrt{(-4)^2-4(1)(29)}}{2(1)}"
"z=\\frac{4\\pm \\sqrt{16-116}}{2}"
"z=\\frac{4\\pm \\sqrt{-100}}{2}"
"z=\\frac{4\\pm 10i}{2}"
"z=\\frac{4}{2}\\pm\\frac{10i}{2}"
"z=4\\pm5i"
hence
"z=4+5i,\\space 4-5i"
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