Answer to Question #192946 in Algebra for Yolljhggjhvgg

Question #192946

z2 -4z+29=0


1
Expert's answer
2021-05-16T18:43:02-0400

By the quadratic formula;

"z=\\frac{-b\\pm \\sqrt{b^2-4ac}}{2a}"


where;

a=1

b=4

c=29


"z=\\frac{-(-4)\\pm\\sqrt{(-4)^2-4(1)(29)}}{2(1)}"


"z=\\frac{4\\pm \\sqrt{16-116}}{2}"


"z=\\frac{4\\pm \\sqrt{-100}}{2}"


"z=\\frac{4\\pm 10i}{2}"


"z=\\frac{4}{2}\\pm\\frac{10i}{2}"


"z=4\\pm5i"


hence


"z=4+5i,\\space 4-5i"


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