If α is in quadrant 4, which quadrant is arccos(tanα) in?
we know that how arccosine is restricted in quadrants,
The arccosine of a positive number is a first quadrant angle, cos-1(+) is in quadrant I.
The arccosine of a negative number is a second quadrant angle,
cos-1(-) is in quadrant II.
and we know that,
tan(x ) is negative in forth quadrant
so,
arccosine of -ve will be in second quadrant.
therefore,
arccos(tanα) will be in second quadrant.
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