Suppose that www is one of the non-real roots of the equation z3=1z^3=1z3=1 .
w^3=1, \ \ w^3-1=0, \ \ (w-1)(1+w+w^2)=0 \ \
w = 1,w \ \bcancel{=}\ 1,w = 1, because 1 is real root of the equation z3=1z^3=1z3=1 . So, w−1 = 0.w-1 \ \bcancel{=}\ 0.w−1 = 0.
We have that 1+w+w2=0.1+w+w^2=0.1+w+w2=0.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments