If G is the abelian group of integers in the mapping T: G → G given by T(x ) = x then prove that as an automorphism
Let "G" be the abelian group of integers. Let us show that the mapping "T: G \u2192 G" given by "T(x ) = x" is an automorphism.
Since "T(x+y)=x+y=T(x)+T(y)," we conclude that "T" is a homomorphism.
Since for "x\\ne y" we get that "T(x)=x\\ne y=T(y)," we conclude that "T" is one-to-one.
Taking into account that for any "y\\in G" we have that "T(y)=y," we conclude that "T" is surjective.
Therefore, "T" is a bijection, and hence is an automorphism.
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