Question #105098
Show that if G is a non-cyclic group of order n, then G has no element of order
n. Further, give an example, with justification, of a non-cyclic group with all its
proper subgroups being cyclic.
1
Expert's answer
2020-03-10T13:01:05-0400

If GG conains element gg of order nn, then GG conains cyclic subgroup <g><g> of order nn.

Then G<g>=G<g>=nn=0|G\setminus<g>|=|G|-|<g>|=n-n=0 (G<g>G\setminus<g> is complement <g><g> in GG ), that is G=<g>G=<g> is a cyclic group. So if GG is a non-cyclic group of order nn , then GG has no element of order nn.


Z2Z2Z_2\oplus Z_2 is a non-cyclic group with cyclic proper subgroups {(0,0)},{(0,0),(0,1)},{(0,0),(1,0)},{(0,0),(1,1)}\{(0,0)\}, \{(0,0),(0,1)\}, \{(0,0),(1,0)\}, \{(0,0),(1,1)\}

Z2Z2Z_2\oplus Z_2 does not have other proper subgroups, because (1,0),(0,1)=(1,0),(1,1)=(1,1),(0,1)=\langle (1,0),(0,1)\rangle=\langle (1,0),(1,1)\rangle=\langle (1,1),(0,1)\rangle=

=Z2Z2=Z_2\oplus Z_2

So every proper subgroup of Z2Z2Z_2\oplus Z_2 is a cyclic group.


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Comments

Assignment Expert
02.11.20, 01:00

Dear Pintoo, please use the panel for submitting new questions.

Pintoo
31.10.20, 13:23

If A and B are two sets such that AUB=Fie, then A intersection B=fie

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