Engineering Answers

For what kind of solution/mixture we may take DAB=DBA?

Water discharge through a pipe of length 50m and diameter 0.5m at 3m3 /s. For this flow, f = 0.025 . Determine the head loss through the model pipe for a scale ratio of 1:10.

The head on a spillway is 1.5m and the discharge is 100m3 /min. What is the head on the scale model of 1:80? Determine the model discharge. 

Water is used to simulate the flow characteristics of oil in an industrial pipeline. The diameter of the test pipeline is 1/10th of that of the industrial pipeline. The viscosities of water and oil are 3.0 x10-4 and 2.9 x 10-2 N.s/m2 while their densities are 1000 and 1720 kg/m3 respectively. If the water velocity in the test pipeline is 10m/s, what is the corresponding oil velocity in the industrial pipeline? 

For an air(A)-water vapour(B) mixture, the partial pressure of the air is 5 pa and the total pressure of the system is 15 pa. The absolute humidity in mass of air/mass of water vapour is

In the context of mass transfer, what happened when tie line coincides with the operating line

a) Minimum no of plates are required. b) Maximum number of plates are required.

c) Optimum no of plates are required.

d) No plates are required.

The solubility of a gaseous substance A(molecular weight 26) in water is given by Henry’s law: pA=105xA ., pA in mm Hg. Convert the equilibrium relation to the following forms, a) yA=m.xA ., if the total pressure is 10 bar; (b) pA=m’CA ,CA in gmol/litre. Also write down the equilibrium relation using the mole ratio unit.

The breathing process within the lungs involves

(a) Diffusion of A through non-diffing (b)Equimolar Counter diffusion

(c) Multicomponent non-equimolar counter diffusion         (d) Not related to diffusion phenomenon.

An artery with dimensions OD = 20 mm and ID = 17 mm is subjected to pressures ranging from 80 mmHg to 130 mmHg. (a) Determine the diameter of the artery of the systolic (highest) and diastolic (lowest) points. The material in the artery follows the relationship σ = kε 2 , with k = 25 MPa. (b) Plot the pressure–radius curve due to the internal pressure from the stress–strain response of the material.