The head on a spillway is 1.5m and the discharge is 100m3 /min. What is the head on the scale model of 1:80? Determine the model discharge.
Head
hPhm=Lr1.5hm=80hm=1.580hm=0.01875m\frac{h_P}{h_m}=L_r\\ \frac{1.5}{h_m}=80\\ h_m= \frac{1.5}{80}\\ h_m= 0.01875 mhmhP=Lrhm1.5=80hm=801.5hm=0.01875m
Discharge
QpQm=(Lr)2.5100Qm=(80)2.5Qm=100802.5Qm=1.747∗10−3m3/mm\frac{Q_p}{Q_m}=(Lr)^{2.5}\\ \frac{100}{Q_m}=(80)^{2.5}\\ Q_m= \frac{100}{80^{2.5}}\\ Q_m= 1.747* 10^{-3}m ^3/mmQmQp=(Lr)2.5Qm100=(80)2.5Qm=802.5100Qm=1.747∗10−3m3/mm
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