Water discharge through a pipe of length 50m and diameter 0.5m at 3m3 /s. For this flow, f = 0.025 . Determine the head loss through the model pipe for a scale ratio of 1:10.
hL=(fLd+ΣKL)v22gh_L = (f\dfrac{L}{d}+ \Sigma K_L)\dfrac{v²}{2g}hL=(fdL+ΣKL)2gv2
v=VA=3π(0.52)/4=15.28m/sv = \dfrac{V}{A} =\dfrac{3}{π(0.5²)/4}= 15.28m/sv=AV=π(0.52)/43=15.28m/s
hL=(0.025(500.5)+110(50))15.2822×9.8h_L = (0.025(\dfrac{50}{0.5}) +\dfrac{1}{10}(50))\dfrac{15.28²}{2×9.8}hL=(0.025(0.550)+101(50))2×9.815.282
=89.34m=89.34m=89.34m
∴\therefore∴ The head loss through the pipe is 89.34m
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