Question #225827

The solubility of a gaseous substance A(molecular weight 26) in water is given by Henry’s law: pA=105xA ., pA in mm Hg. Convert the equilibrium relation to the following forms, a) yA=m.xA ., if the total pressure is 10 bar; (b) pA=m’CA ,CA in gmol/litre. Also write down the equilibrium relation using the mole ratio unit.


1
Expert's answer
2021-08-16T02:19:15-0400

Part a

We know that yA=pAP    pA=yAPy_A= \frac{p_A}{P} \implies p_A=y_AP

Putting in the equation

yA7500=105xAyA=0.014xAy_A*7500=105 x_A\\ y_A=0.014 x_A


Part b

pA=105xAxA=nAnA+nBpA=105 nAnA+nBpA=105 cAcA+cBp_A=105x_A\\ x_A=\frac{n_A}{n_A+n_B}\\ p_A=105 \space\frac{n_A}{n_A+n_B}\\ p_A= 105 \space\frac{c_A}{c_A+c_B}


Part C

Given equilibrium relation

yA=0.014xAy_A=0.014x_A

Convert this to mole ratio unit

Y and X - mole ratio in vapour

X=xA1xAY=yA1yAX=xA1+xAY=yA1+yAYA1+YA=0.014XA1+XAX= \frac{x_A}{1-x_A}\\ Y= \frac{y_A}{1-y_A}\\ X= \frac{x_A}{1+x_A}\\ Y= \frac{y_A}{1+y_A}\\ \frac{Y_A}{1+Y_A}=0.014 \frac{X_A}{1+X_A}\\


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS