Question #224906

One thousand kilograms per hour of a mixture of benzene (B) and Toluene (T) containing 60% benzene by mass is separated by distillation into two fractions. The mass flowrate of the benzene (B) in the top stream is 500 kg (B) /h and that of toluene in the bottom stream is 485 kg (T) / h. The unit operates at steady state.

3.1.1. Draw a schematic diagram showing all the relevant streams in the distillation unit. (8)

3.1.2. Write the basis for calculation.


1
Expert's answer
2021-08-11T07:28:35-0400


Overall balance

1000=D+B.........(1)1000=D+B.........(1)

Applying benzene balance

(1000)(0.5)=D×D+B×B=450+B×BB×B=50(1000)(0.5)=D \times D + B \times B = 450 + B \times B\\ B \times B =50

This is the benzene flow rate at the bottom


Applying tolere balance

(1000)(0.5)=DyD+ByB=DyD+475DyD=25(1000)(0.5)=D y D + B y B = DyD+475\\ DyD= 25

This is the tolere flow rate at the top


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