y2y′−y3tan(x)=sin(x)cos2(x)AfirstorderBernoulliODEhastheformofy′+p(x)y=q(x)yny′−tan(x)y=sin(x)cos2(x)y−2Thegeneralsolutionisobtainedbysubstitutingv=y1−nandsolving1−n1v′+p(x)v=q(x)ν=−2cos3(x)+cos3(x)c1y3=−2cos3(x)+cos3(x)c1y=2cos(x)2323−cos6(x)+3y=2cos(x)2323−cos6(x)+3
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