Question #224872

Solve ∫y=0 ^ 1 ∫x=y^ 2 ^ 1∫z=0 ^ 1-x x dzdxdy


1
Expert's answer
2021-08-18T09:46:01-0400

y=01x=y21z=01xxdzdxdy=x(x+1)=01y21x(x+1)dxdy=01(1y421y63)dy=435\int_{y=0}^1 ∫_{x=y^ 2} ^ 1∫_{z=0} ^ {1-x} x dzdxdy\\ =x\left(-x+1\right)\\ =\int _0^1\int _{y^2}^1x\left(-x+1\right)dxdy\\ =\int _0^1\left(\frac{1-y^4}{2}-\frac{1-y^6}{3}\right)dy\\ =\frac{4}{35}


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