Given :-
Arrival rate (λ)=30 per hours.
Service rate (μ)=45 per hours.
ρ=μλ=4530=0.6666
Hence,
Probability of having "n" customers is
P=ρn(1−ρ)=(0.666)n(1−0.666)=(0.666)n(0.3333)
1) What is the probability of having "zero" customer in the system
Hence, "0" customer have
P=(0.666)0(0.3333)P=0.333
2) What is the probability of having "8" customer in the system
Hence, 8 customer have
P=(0.666)8(0.3333)P=0.012889
3) What is the probability of having "12" customer in the system
Hence, 12 customer have
P=(0.666)12(0.3333)P=0.00025382013
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