Answer to Question #83815 in Mechanical Engineering for GOPAL JHA

Question #83815
A mixture of air and water vapour at 1.013 bar and 16 degree C has a dew
point of 5degree C. Calculate the relative and specific humidity’s?
1
Expert's answer
2018-12-17T07:24:23-0500

The saturaion pressures at the given temperatures are

Ps(5oC)=872.6Pa,Ps(16oC)=1818.8Pa,P_s(5^o C)=872.6 Pa,\\ P_s(16^o C)=1818.8 Pa,

The relative humudity is given by

ϕ=Ps(5oC)Ps(16oC)ϕ=872.61818.8=0.480\phi=\frac{P_s(5^o C)}{P_s(16^o C)}\\ \phi= \frac{872.6}{1818.8}=0.480

The specific humidity is given by

x=Ps(5oC)PPs(5oC)x=872.61.013×105872.6=0.0054kg/kg.x=\frac{P_s(5^o C)}{P-P_s(5^o C)}\\ x= \frac{872.6}{1.013\times10^5-872.6}=0.0054 kg/kg.

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