Question

Calculate the maximum value of the e.m.f. generated in a coil which is rotating at 50 rev/s in a uniform magnetic field of 0.8 Wb/m2. The coil is wound on a square former having sides 5 cm in length and is wound with 300 turns

Answer 1

Maximum value

$Emax= BAN\omega$

$B = 0.8 \frac{wb}{m^3}$

$A = 5\times 5 = 0.0025m^2$

$\omega = 50 \frac{rev}{s} =100 \pi \frac{rad}{s}$

$Emax= 0.08 \times 0.0025 \times 300 \times 100\pi = 188.5V$