Question

A ball is thrown vertically upward with a speed of 15 m/s. Determine the time of flight when it 
returns to its original position.

Accepted Answer

U = 15 M/S V = 0 M/S  V = U +AT 0 = 15-10T T = 1.5 SEC AS THE BALL
WILL RETURN TO ITS ORIGINAL POSITION, THE TIME TAKEN FOR THE BALL TO
GO UP WILL BE SAME AS THAT IT WILL TAKE TO COME DOWN.  HENCE TOTAL
TIME TAKEN = 3 SEC.

Question #245080

Expert's answer

$u = 15 m/s$ $v = 0 m/s$ $v = u +at$ $0 = 15-10t$ $t = 1.5 sec$ As the ball will return to its original position, the time taken for the ball to go up will be same as that it will take to come down. Hence total time taken = 3 sec.

Question #245080

Expert's answer

u=15m/su = 15 m/su=15m/s v=0m/sv = 0 m/sv=0m/s v=u+atv = u +atv=u+at 0=15−10t0 = 15-10t0=15−10t t=1.5sect = 1.5 sect=1.5sec As the ball will return to its original position, the time taken for the ball to go up will be same as that it will take to come down. Hence total time taken = 3 sec.

$u = 15 m/s$ $v = 0 m/s$ $v = u +at$ $0 = 15-10t$ $t = 1.5 sec$ As the ball will return to its original position, the time taken for the ball to go up will be same as that it will take to come down. Hence total time taken = 3 sec.