Question #234071

6. A tank is in the form of a right circular cylinder with hemispherical ends. The overall length of the tank is

4 meters and the diameter of the hemisphere is 1 meter. If a pump discharges a fluid whose density is

1.2 kg m /Liter in this tank at a rate of225 liters per minute determine a.) Weight of liquid inside the tank if

it is half full. b) total time to fill the tank assuming it is initially empty.


Expert's answer

Let d=d= the diameter of the hemisphere, l=l=the overall length of the tank

Find the volume of the hemisphere


V1=12(43π(d2)3)=πd312V_1=\dfrac{1}{2}\big(\dfrac{4}{3}\pi(\dfrac{d}{2})^3\big)=\dfrac{\pi d^3}{12}

Find the volume of the right circular cylinder


V2=π(d2)2(l2(d2))=πd2(ld)8V_2=\pi\big(\dfrac{d}{2}\big)^2(l-2(\dfrac{d}{2}))=\dfrac{\pi d^2(l-d)}{8}

Find the mass of liquid inside the tank if it is half full


m=ρ(V1+V2)=ρπd2(2d+3l3d)24m=\rho(V_1+V_2)=\rho\dfrac{\pi d^2(2d+3l-3d)}{24}

=ρπd2(3ld)24=\rho\dfrac{\pi d^2(3l-d)}{24}

m=1.2 kgm103 m3π(1 m)2(3(4 m)1 m)24m=1.2\ \dfrac{kgm}{10^{-3}\ m^3}\cdot\dfrac{\pi (1\ m)^2(3(4\ m)-1\ m)}{24}

=550π kgm1728 kg=550\pi\ kgm\approx1728\ kg

Find the mass of liquid inside the tank if it is half full


W=mgW=mg

W=550π kgm(9.81 m/s2)16950 NW=550\pi\ kgm(9.81\ m/s^2)\approx16950\ N


V=2(12)(43π(d2)3)=πd36V=2(\dfrac{1}{2})\big(\dfrac{4}{3}\pi(\dfrac{d}{2})^3\big)=\dfrac{\pi d^3}{6}

b) Find the volume of the tank


V=2V1+V2V=2V_1+V_2

=2(πd312)+πd2(ld)8=2(\dfrac{\pi d^3}{12})+\dfrac{\pi d^2(l-d)}{8}

=πd2(4d+3l3d)24=\dfrac{\pi d^2(4d+3l-3d)}{24}

=πd2(3l+d)24=\dfrac{\pi d^2(3l+d)}{24}

V=π(1 m)2(3(4 m)+1 m)24=13π24 m3V=\dfrac{\pi (1\ m)^2(3(4\ m)+1\ m)}{24}=\dfrac{13\pi}{24}\ m^3

Find the total time to fill the tank assuming it is initially empty


t=13π24 m30.225 m3/min7.6 mint=\dfrac{\dfrac{13\pi}{24}\ m^3}{0.225 \ m^3/min}\approx7.6\ min


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