Question #234071

6. A tank is in the form of a right circular cylinder with hemispherical ends. The overall length of the tank is

4 meters and the diameter of the hemisphere is 1 meter. If a pump discharges a fluid whose density is

1.2 kg m /Liter in this tank at a rate of225 liters per minute determine a.) Weight of liquid inside the tank if

it is half full. b) total time to fill the tank assuming it is initially empty.


1
Expert's answer
2021-09-09T00:33:20-0400

Let d=d= the diameter of the hemisphere, l=l=the overall length of the tank

Find the volume of the hemisphere


V1=12(43π(d2)3)=πd312V_1=\dfrac{1}{2}\big(\dfrac{4}{3}\pi(\dfrac{d}{2})^3\big)=\dfrac{\pi d^3}{12}

Find the volume of the right circular cylinder


V2=π(d2)2(l2(d2))=πd2(ld)8V_2=\pi\big(\dfrac{d}{2}\big)^2(l-2(\dfrac{d}{2}))=\dfrac{\pi d^2(l-d)}{8}

Find the mass of liquid inside the tank if it is half full


m=ρ(V1+V2)=ρπd2(2d+3l3d)24m=\rho(V_1+V_2)=\rho\dfrac{\pi d^2(2d+3l-3d)}{24}

=ρπd2(3ld)24=\rho\dfrac{\pi d^2(3l-d)}{24}

m=1.2 kgm103 m3π(1 m)2(3(4 m)1 m)24m=1.2\ \dfrac{kgm}{10^{-3}\ m^3}\cdot\dfrac{\pi (1\ m)^2(3(4\ m)-1\ m)}{24}

=550π kgm1728 kg=550\pi\ kgm\approx1728\ kg

Find the mass of liquid inside the tank if it is half full


W=mgW=mg

W=550π kgm(9.81 m/s2)16950 NW=550\pi\ kgm(9.81\ m/s^2)\approx16950\ N


V=2(12)(43π(d2)3)=πd36V=2(\dfrac{1}{2})\big(\dfrac{4}{3}\pi(\dfrac{d}{2})^3\big)=\dfrac{\pi d^3}{6}

b) Find the volume of the tank


V=2V1+V2V=2V_1+V_2

=2(πd312)+πd2(ld)8=2(\dfrac{\pi d^3}{12})+\dfrac{\pi d^2(l-d)}{8}

=πd2(4d+3l3d)24=\dfrac{\pi d^2(4d+3l-3d)}{24}

=πd2(3l+d)24=\dfrac{\pi d^2(3l+d)}{24}

V=π(1 m)2(3(4 m)+1 m)24=13π24 m3V=\dfrac{\pi (1\ m)^2(3(4\ m)+1\ m)}{24}=\dfrac{13\pi}{24}\ m^3

Find the total time to fill the tank assuming it is initially empty


t=13π24 m30.225 m3/min7.6 mint=\dfrac{\dfrac{13\pi}{24}\ m^3}{0.225 \ m^3/min}\approx7.6\ min


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