Answer to Question #234068 in Mechanical Engineering for Randal Rodriguez

Question #234068

4. What is the pressure (psia) at the base of a 8 ft liquid column with atmospheric pressure 755 mm Hg, if

the fluid is a) water, b) glycerin (SG = 1.25), c) Oil (SG = 0.750)


1
Expert's answer
2021-09-08T07:44:17-0400

P=Patm+ρghP =P_{\text{atm}}+\rho gh


Patm=755 mmHg760 mmHg×101325 PaP_{\text{atm}} =\dfrac{755\text{ mmHg}}{760\text{ mmHg}}× 101325\ Pa

=100658Pa=100658 Pa

h=8 ft=2.44 mh = 8\ ft= 2.44\ m


a) P=Patm+ρghP=100658+1000(9.8)(2.44)=124570 PaP =P_{\text{atm}}+\rho gh\\ P = 100658 + 1000(9.8)(2.44) = 124570\ PaP=Patm+ρghP=100658+1000(9.8)(2.44)(1.25)=P =P_{\text{atm}}+\rho gh\\ P = 100658 + 1000(9.8)(2.44)(1.25) =\\


b)P=Patm+ρghP=100658+1000(9.8)(2.44)(1.25)=130548 PaP =P_{\text{atm}}+\rho gh\\ P = 100658 + 1000(9.8)(2.44)(1.25)\\= 130548 \ Pa


c)

P=Patm+ρghP=100658+1000(9.8)(2.44)(0.75)=118592 PaP =P_{\text{atm}}+\rho gh\\ P = 100658 + 1000(9.8)(2.44)(0.75)\\ = 118592 \ Pa

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