Answer to Question #224594 in Mechanical Engineering for Unknown346307

Question

The 6-pole,wound-rotor induction motor is excited by a 3-phase, 60 Hz source. Calculate the

frequency of the rotor current under the following conditions:

(i) at standstill

(ii) motor turning at 500 rpm in the same direction as the revolving field

(iii) motor turning at 500 rpm in the opposite direction to the revolving field

(iv) motor turning at 2000 rpm in the same direction as the revolving field

Answer 1

Synchronous Speed $=\frac{120f}{P}=\frac{120\times60}{6} =1200$

slip $= \frac{N_s-N}{N}$

1) at standstill Rotor Frequency is 60 Hz

2) motor turning at 500 rpm in the same direction as the revolving field

Rotor Frequency $=sf= (\frac{N_s-N}{N})\times f =(\frac{1200-500}{500})\times 60 =84$ Hz

3) motor turning at 500 rpm in the opposite direction to the revolving field

Rotor Frequency $=sf= (\frac{N_s+N}{N})\times f =(\frac{1200+500}{500})\times 60 =85$ Hz

4) motor turning at 2000 rpm in the same direction as the revolving field

Rotor Frequency $=sf= (\frac{N_s-N}{N})\times f =(\frac{1200-2000}{2000})\times 60 =24$ Hz