Answer to Question #218252 in Mechanical Engineering for Sumeet Wagh

Question

An open topped tank with a base area of 1 m2 contains a layer of water 0.5 m deep below an oil

later 1 m deep, as shown in the figure below. Determine the absolute pressure at 0.5 m below

the surface and at the bottom of the tank. Assume the densities of water and oil are 1000 kg/m3

and 850 kg/m3 respectively. Also determine the total weight of the fluid if the base area is 1 m2

Answer 1

$$p_1=101325+(850)(9.8)(0.5)=105490\ Pa$$

$$p_2=101325+(850)(9.8)(1)+(1000)(9.8)(0.5)\\=114555\ Pa$$

$$W=(114555-101325)(1)=13230\ N$$