Question #217960

A compressed air tank contains 5 kg of air at a temperature of 80 °C. A gauge pressure meter on the tank reads 300 kPa. Determine the volume of the tank and state the assumption made


Expert's answer

Consider Ideal gas law, express ρ\rho as mass per volume

p=ρTRp = \rho TR


p=mVTRp = \frac{m}{V}TR


V=mpTR=5kg.353K.287.05jkgK(300+101.6)103pa=1.2625m3V = \frac{m}{p}TR = \frac{ 5 kg.353K.287.05\frac{j}{kgK}}{(300+101.6)10^3 pa}= 1.2625 m^3



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