Air at 1 bar and 27°C is heated in a non flow system at constant pressure to 177°C. Heat is supplied from a constant temperature reservoir at 577 °C. The atmospheric temperature is 20 °C. Calculate the available energy.
Heat received by the air is given by "Q = m_ac_v (T_2\u2032 \u2013 T_1\u2032)"
Say Q=600, "\\implies 600 = 1\u00d7 0.81 (T_2\u2032 \u2013 400)"
"T_\n2\u2032 =\\frac{ 600}{\n3 \u00d7 0.81}\n+ 400 = 646.9 K \\space say \\space 647 K"
Available energy with the source "(1200 \u2013 290) \u00d7 \\frac{ 600}{\n1200} = 455 kJ"
Change in entropy of the air "= m_ac_v\nlog\n_e\n\\frac{T_2}{ T_1}\n\n= 3 \u00d7 0.81 \u00d7 log_e\n\\frac{647}{400}\n= 1.168 kJ\/K"
Unavailability of the air "= 290 \u00d7 1.168 = 338.72 kJ"
Available energy with the air "= 600 \u2013 338.72 = 261.28 kJ"
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