Question #210316

What is the solution?


A man holds a ball of weight 114g at rest in his hand. He then throws the ball vertically upward. In this process, his hand moves up 0.6m and the ball leaves his hand with an upward velocity of 15 m/s. Find the force with which the man pushes on the ball.


Answer = 22.5 N


Expert's answer

The kinetic energy of the ball is


EK=mv22E_K=\dfrac{mv^2}{2}

EK=0.114 kg(15 m/s)22=12.825 JE_K=\dfrac{0.114\ kg(15\ m/s)^2}{2}=12.825\ J

Then


EK=Fs=>F=EKsE_K=Fs=>F=\dfrac{E_K}{s}

F=12.825 J0.6 m=21.375 NF=\dfrac{12.825\ J}{0.6\ m}=21.375\ N


LATEST TUTORIALS
APPROVED BY CLIENTS