Question

first and last gear having teeth 30 and 50 respectively of a simple gear train what will be train value and speed ratio gear respectively if first gear is driving gear

Answer 1

Train value

$= \frac{Driving \space gear}{Driven \space gear}= \frac{30}{50}= \frac{3}{5}$

Speed ratio gear

$= \frac{Driven \space gear}{Driving \space gear}= \frac{50}{30}= \frac{5}{3}$