Question #209035

A vapour power plant working on Rankine cycle operates between boiler pressure of 500KN/M2 and condenser pressure of 0.06 bar calculate (1) The Thermal Efficiency (2) Work ratio (3) Specific steam consumption for the cycle.


Expert's answer

Form the tables h1=2747.5;h2=151.5+0.88∗2416=2277.59;h3=151.5;h4=640h_1= 2747.5; h_2= 151.5+0.88*2416=2277.59; h_3= 151.5; h_4=640


(1) The Thermal Efficiency

ηT=h1−h2h1−h4∗100=2747.5−2277.592747.5−640∗100=22%η_T= \frac{h_1-h_2}{h_1-h_4}*100= \frac{2747.5-2277.59}{2747.5-640}*100= 22 \%


(2) Work ratio

Work ratio =1−WPWT=1−h4−h3h1−h4=1−640−151.52747.5−640=0.7681=1-\frac{W_P}{W_T}=1-\frac{h_4-h_3}{h_1-h_4}=1-\frac{640-151.5}{2747.5-640}=0.7681


(3) Specific steam consumption for the cycle.

SSC=3600Wnet=3600WT−WP=36002107−488=36001618.5=2.22kg/kWhSSC = \frac{3600}{W_{net}} = \frac{3600}{W_T-W_P}= \frac{3600}{2107-488} = \frac{3600}{1618.5}=2.22 kg/kWh


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