Form the tables h1=2747.5;h2=151.5+0.88∗2416=2277.59;h3=151.5;h4=640
(1) The Thermal Efficiency
ηT=h1−h4h1−h2∗100=2747.5−6402747.5−2277.59∗100=22%
(2) Work ratio
Work ratio =1−WTWP=1−h1−h4h4−h3=1−2747.5−640640−151.5=0.7681
(3) Specific steam consumption for the cycle.
SSC=Wnet3600=WT−WP3600=2107−4883600=1618.53600=2.22kg/kWh
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