VBA=1.8m/sec;VBC=2∗0.5=1m/sec;VC=VCD=3.1∗0.5=1.55m/sec
VE=34∗0.5=1.7m/sec
For angular velocity of BC and CD
BC=BCVBC=0.08751=11.43rad/sec;CD=CDVCD=0.0501.55=31rad/sec
aBAr=BA(VBA)2=0.025(1.8)2=129.6m/sec
aCBr=CB(VCB)2=0.0875(1)2=11.43m/sec
aCDr=CD(VCD)2=0.0.050(1.55)2=48.05m/sec
No Tangential component of BA
ae=8.9∗12=106.8m/sec
For angular accn of BC and CD
aBCt=6.3∗12=75.6m/sec
aBCt=(BC).αBC=0.087575.6=864rad/sec
aCDt=5.2∗12=62.4m/sec2=CDaCDt=0.05062.4=1248rad/sec2
Comments