Question

A compound train consists of six gears. The number of teeth on the gears are as follows:

Gear : AB C DE F

No. of teeth : 60 40 50 25 30 24

The gears B and C are on one shaft while the gears D and E are on another shaft. The gear A drives gear B, gear C drives gear D and gear E drives gear F. If the gear A transmits 1.5 kW at 100 r.p.m. and the gear

train has an efficiency of 80 per cent, find the torque on gear F.

Answer 1

Given that :

$T_A=60$

$T_A=40$

$T_C=50$

$T_D=25$

$T_E=30$

$T_F=24$

Velocity ratio (VR)$=\frac{No \space of \space teeth \space on \space driven \space gears }{No \space of \space teeth \space on \space drives \space gears }$

Gears A,C and E are drives gears while gears B,D, and F are driven gears

So, $\frac{N_A}{N_F}=\frac{T_B*T_D*T_F}{T_A*T_C*T_E}$

$\frac{100}{N_F}=\frac{40*25*24}{60*50*30}$

Angular speed of gear F ,$N_F=375rpm$