A compound train consists of six gears. The number of teeth on the gears are as follows:
Gear : AB C DE F
No. of teeth : 60 40 50 25 30 24
The gears B and C are on one shaft while the gears D and E are on another shaft. The gear A drives gear B, gear C drives gear D and gear E drives gear F. If the gear A transmits 1.5 kW at 100 r.p.m. and the gear
train has an efficiency of 80 per cent, find the torque on gear F.
Given that :
"T_A=60"
"T_A=40"
"T_C=50"
"T_D=25"
"T_E=30"
"T_F=24"
Velocity ratio (VR)"=\\frac{No \\space of \\space teeth \\space on \\space driven \\space gears }{No \\space of \\space teeth \\space on \\space drives \\space gears }"
Gears A,C and E are drives gears while gears B,D, and F are driven gears
So, "\\frac{N_A}{N_F}=\\frac{T_B*T_D*T_F}{T_A*T_C*T_E}"
"\\frac{100}{N_F}=\\frac{40*25*24}{60*50*30}"
Angular speed of gear F ,"N_F=375rpm"
Comments
Leave a comment