(a) percentage decrease
"\\frac{V_2}{V_1}\\times100"
"V_1=0.5m^3"
"\\frac{p_1}{p_2}=(\\frac{V_2}{V_1})^{1.4}=\\frac{1}{10}=(\\frac{V_2}{0.50})^{1.4}=V_2=0.09653"
"=\\frac{0.09653}{0.5}\\times100=19.306\\%"
(b) Air standard efficiency
"\\eta=1-\\frac{T_1}{T_2}=1"
"T_2=T_1(\\frac{p_2}{p_1})^{\\frac{0.4}{1.4}}=(27+273)(10)^{\\frac{0.4}{1.4}}=579.2K"
"\\eta=1-\\frac{300}{579.2}=48.2\\%"
(c)mean effective pressure
"P_{mean}=\\frac{W}{V_3}"
W"=\\eta Q_a=\\frac{48.2}{100}\\times 200kJ=94.47kJ"
"V_s=V_1-V_2=0.5-0.09653=0.40347m^3"
"P_{mean} =\\frac{96.41}{0.40347}=238.95kPa"
(d) Ideal power
"P=w\\times N=96.41\\times1200=19282 KW"
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