Answer to Question #175923 in Mechanical Engineering for luke

Question #175923

A spring extends 2 inches when loaded vertically with 4 lbs. This weight was pulled further down by 3 inches an was released from rest. Determine the frequency of vibration in rad per second


1
Expert's answer
2021-04-01T01:12:59-0400

"k = f\/x"

where; k is the spring constant.

f is the force applied.

x is the extension on the spring.

4lbs = 1.81 kgs

2inches = 0.0508 m

3inches = 0.0762 m

k= 18.1Newtons/ 0.0508m

= 356.3 N/m

force required to extend the spring to a further 3inches (0.0762m)

"f = kx"

= 356.3 N/m *0.0762

= 27.15N

"W (Rads\/sec) = \\sqrt {k\/m}"

"= \\sqrt {356.3\/2.715 }"


= 11.455 rads/sec


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS