Question #175922

A spring extends 2 inches when loaded vertically with 4 lbs. This weight was pulled further down by 3 inches an was released from rest. Determine the frequency of vibration in Hz


Expert's answer

Given as,

Mass attached (m)=4lbs

Extension in the spring(y)=3inches=0.25 ft

The spring constant(k)=m×gy=4×32.20.25=515.2lbf/ft\frac{m×g}{y}=\frac{4×32.2}{0.25}=515.2\: lb-f/ft

The natural frequency is given by,

f=12πkm=1.81Hzf= \frac{1}{2\pi} \sqrt{\frac{k}{m}}=1.81 Hz


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